First slide
Rectilinear Motion
Question

A particle is thrown up inside a stationary lift of sufficient height. The time off light is T. Now it is thrown again with same initial speed v0 with respect to lift. At the time of
second throw, lift is moving up with speed v0 and uniform acceleration g upward (the acceleration due to gravity). The new time of flight is

Moderate
Solution

With respect to lift initial speed = v0
Acceleration =- 2g

 Displacement =0S=ut+12at2 0=v0T+12×2g×T2 T=v0g=12×2v0g=12T

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