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Q.

A particle thrown up vertically reaches its highest point in time t1 and returns to the ground in time t2.The air resistance exerts a constant force on the particle opposite to its direction of motion, then

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a

t1>t2

b

t1=t2

c

t1

d

none of above

answer is C.

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Detailed Solution

See figure For upward motion0=u−a1t1 or u=a1t1and h=ut1−12a1t12∴h=a1t1t1−12a1t12=12a1t12For downward motionh=12a2t2∴t2t1=a1a2=[g+(R/m)][g−(R/m)]or t1
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