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Questions  

A particle is thrown with the speed u at an angle α with the horizontal. When the particle makes an angle β with the horizontal, its speed will be:

a
u cos α
b
u cos α sec β
c
u cos α cos β
d
u sec α sec β

detailed solution

Correct option is B

As horizontal velocity = constantSo, v cos β= u cos α ⇒v=ucosα secβ

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