A particle is thrown with a speed u at an angle θ with the horizontal. When the particle makes an angle ϕ with the horizontal, its speed changes to ν, where
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a
ν = u cos θ
b
ν = u cos θ cos ϕ
c
ν = u cosθ sec ϕ
d
ν = u sec θ cos ϕ
answer is C.
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Detailed Solution
Horizontal component of velocity remains unchanged.Hence, vcosϕ=ucosθ∴ v=ucosθsecϕ