A particle is thrown with a speed u at an angle θ with the horizontal. When the particle makes an angle ϕ with the horizontal, its speed changes to V, which is equal to?
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a
u cos θ
b
u cos θ cos ϕ
c
u cos θ sec ϕ
d
u sec θ cos ϕ
answer is C.
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Detailed Solution
In projectile motion, the horizontal component velocity remains constant throughout the motion, so u cos θ=v cos ϕ v=u cosθcosϕ v =u cos θ secϕ