First slide

Projection Under uniform Acceleration

Question

A particle is thrown with a velocity u at an angle θ from the horizontal. Another particle is thrown with the same velocity at an angle θ from the vertical. The ratio of times of flight of the two particles will be

Moderate

A

Tan 2θ : 1
B

Cot 2θ : 1
C

Tanθ : 1
D

Cotθ : 1

Solution

${T_1} = \frac{{2u\sin \theta }}{g},\,\,{T_2} = \frac{{2u\sin ({{90}^0} - \theta )}}{g}$
$\Rightarrow {T_2} = \frac{{2u\cos \theta }}{g};\;\frac{{{T_1}}}{{{T_2}}} = Tan\theta :1$

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