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A particle travels in a straight line, such that for a short time $2 s \leq t \leq 6 s$ , its motion is described by $v = (4 / a) m / s$ , where $a$ is in $m / s^{2}$ . If $v = 6 m / s$ when $t = 2 s$ , determine the particle's acceleration when $t = 3 s$ .

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1.603 m/s2

2.603 m/s2

0.903 m/s2

0.603 m/s2

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detailed solution

Correct option is D

a=4v or dvdt=4v ∴ ∫6vvdv=∫2t4dt ∴ v22-18=4t-8 v=8t+20 ∴ a=dvdt=48t+20 At t=3 s, a=0.603 m/s2

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A particle travels in a straight line, such that for a short time 2 s≤t≤6 s, its motion is described by v=(4/a)m/s, where a is in m/s2. If v=6 m/s when t=2 s, determine the particle's acceleration when t=3 s.

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A particle travels in a straight line, such that for a short time $2 s \leq t \leq 6 s$ , its motion is described by $v = (4 / a) m / s$ , where $a$ is in $m / s^{2}$ . If $v = 6 m / s$ when $t = 2 s$ , determine the particle's acceleration when $t = 3 s$ .