A particle under the action of a SHM has a period of 3 s and under the effect of another it has a period 4 s. What will be its period under the combined action of both the SHM's in the same direction?
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a
7 s
b
5 s
c
2.4 s
d
0.4 s
answer is C.
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Detailed Solution
T=2πmk or T∝1kT has increased 43times. Hence, k'=916kWhen both are combined, knet =k+k'=2516k or 2516timesHence, new time period will become 43times of 3 s or 2.4 s.