A particle undergoes SHM governed by the equation x=x0cosωt−π4. Also, if acceleration of the particle can be written as a=Acos(ωt+δ), then
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a
A=x0ω2,δ=3π4
b
A=x0,δ=−π4
c
A=x0ω2,δ=π4
d
A=x0ω2,δ=−π4
answer is A.
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Detailed Solution
Given. x=x0cosωt−π4Velocity, ν=dxdt=−x0ωsinωt−π4Acceleration,a=dvdt=−x0ω2cosωt−π4x0ω2cosπ+ωt−π4x0ω2cosωt+3π4Comparing it with acceleration,a=Acos(ωt+δ), we getA=x0ω2,δ=3π4