A particle undergoes uniform circular motion on a horizontal xy plane. At time t = 0, it moves through coordinates (3.0 m, 0) with velocity $\overrightarrow{\mathrm{v}}=(6.0\mathrm{m}/\mathrm{s})\hat{\mathrm{j}}$. At t = 5.0 s, it moves through (11.0 m, 0) with velocity $\overrightarrow{\mathrm{v}}=(-6.0\mathrm{m}/\mathrm{s})\hat{\mathrm{j}}$. What is its acceleration at t = 2.5 s?

• A

  $\left(9.0\mathrm{m}/{\mathrm{s}}^2\right)\hat{\mathrm{j}}$

• B

  $\left(4.0\mathrm{m}/{\mathrm{s}}^2\right)\hat{\mathrm{j}}$

• C

  $\left(-9.0\mathrm{m}/{\mathrm{s}}^2\right)\hat{\mathrm{j}}$

• D

  $\left(-4.0\mathrm{m}/{\mathrm{s}}^2\right)\hat{\mathrm{j}}$