Q.

A particle is undergoing SHM along a straight line so that its period is 12 s. The  time it takes in traversing a distance equal to half its amplitude from the  equilibrium position is

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a

3 s

b

2 s

c

1 s

d

0.5 s

answer is C.

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Detailed Solution

y=Asin⁡ωtA2=Asin⁡2π12t12=sin⁡π6t ∴πt6=π6⇒t=1s
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A particle is undergoing SHM along a straight line so that its period is 12 s. The  time it takes in traversing a distance equal to half its amplitude from the  equilibrium position is