Questions
A particle is undergoing SHM along a straight line so that its period is 12 s. The time it takes in traversing a distance equal to half its amplitude from the equilibrium position is
detailed solution
Correct option is C
y=AsinωtA2=Asin2π12t12=sinπ6t ∴πt6=π6⇒t=1sTalk to our academic expert!
Similar Questions
A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is . What must be the least period of these oscillations, so that the object is not detached from the platform
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