First slide
Instantaneous acceleration
Question

A particle of unit mass undergoes one-dimensional motion such that its velocity varies according t
vx=βx-2n  where β and n are constants and x is the position of the particle. The acceleration of the particle as a function of x, is given by :

Moderate
Solution

v=βx2n
So, dvdx=2nβx2n1
Nowa=vdvdx=βx2n2nβx2n1
a=22x4n1

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