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Q.

A particle is vibrating in S.H.M. Its velocities are v1 and v2 when the displacements from the mean position are y1 and y2, respectively, then its time period is

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a

2πy12+y22v12+v22

b

2πv12+v22y12+y22

c

2πv22−v12y12−y22

d

2πy12−y22v22−v12

answer is D.

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Detailed Solution

v2=ω2a2−x2 ⇒v12=ω2a2−y12      .....(1) ⇒v22=ω2a2−y22      ......(2)From (1) and (2), we getT=2πy12−y22v22−v12
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