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Q.

A particle is vibrating in a simple harmonic motion with amplitude 3 cm. When the restoring force acting on the particle is half of the maximum possible restoring force, find the ratio of kinetic energy of the particle to its potential energy.

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a

4

b

3

c

22

d

3

answer is B.

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Detailed Solution

Restoring force acting on the particle F=mω2x where x is the distance from equilibrium position. So Fmax=mω2A and when F=12Fmax, x=A2∴ Kinetic energy K=12mωA2−A222=38mω2A2Potential energy (V)=12mω2A22=18mω2A2∴ KU=3
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