Questions
A particle is vibrating in a simple harmonic motion with amplitude 3 cm. When the restoring force acting on the particle is half of the maximum possible restoring force, find the ratio of kinetic energy of the particle to its potential energy.
detailed solution
Correct option is B
Restoring force acting on the particle F=mω2x where x is the distance from equilibrium position. So Fmax=mω2A and when F=12Fmax, x=A2∴ Kinetic energy K=12mωA2−A222=38mω2A2Potential energy (V)=12mω2A22=18mω2A2∴ KU=3Talk to our academic expert!
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