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Q.

A particle which is experiencing a force given by F→=3i^−12j^ undergoes a displacement of  d→=4i^. If the particle had a kinetic energy of  3J at the beginning of the displacement , what is the kinetic energy at the end of the displacement?

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Detailed Solution

According to work energy theoremWork done = Change in kinetic energy⇒W=ΔKE⇒W=KEf−KEi⇒KEf=W+KEi⇒KEf=F→⋅S→+KEi⇒KEf=(3i^−12j^)⋅(4i^)+3⇒KEf=12+3⇒KEf=15J
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