First slide
Work
Question

A particle which is experiencing a force given by F=3i^12j^ undergoes a displacement of  d=4i^. If the particle had a kinetic energy of  3J at the beginning of the displacement , what is the kinetic energy at the end of the displacement?

Moderate
Solution

According to work energy theorem
Work done = Change in kinetic energy
W=ΔKEW=KEfKEiKEf=W+KEiKEf=FS+KEiKEf=(3i^12j^)(4i^)+3KEf=12+3KEf=15J

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