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Q.

A particle is whirled in a circular path  by a string with a constant angular velocity and its angular momentum is L. If the length of the string is now halved keeping the angular velocity same, the angular momentum is:

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a

L4

b

L

c

2L

d

L2

answer is A.

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Detailed Solution

L = mr2ω, Now Given r' = r2 and ω' = ω              L' = mωr24 = L4
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