Questions
A particle is whirled in a circular path by a string with a constant angular velocity and its angular momentum is L. If the length of the string is now halved keeping the angular velocity same, the angular momentum is:
detailed solution
Correct option is A
L = mr2ω, Now Given r' = r2 and ω' = ω L' = mωr24 = L4Talk to our academic expert!
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The moment of inertia (I) and the angular momentum (L) are related by the expression [J&K CET 2013]
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