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A particle whose speed is 50 m/s moves along the line from A(2, 1) to B(9, 25). Find the velocity vector in the form of ai^+bj^

a
(7i^+24j^) m/s
b
2(7i^+24j^) m/s
c
4(7i^+24j^) m/s
d
5(7i^+24j^) m/s

detailed solution

Correct option is B

V→=  50(AB^)|AB¯| = (9−2)i^+(25−1)j^  =  (7i^+24j^)|AB¯| = (7)2+(24)2AB^ = (7i^+24j^)(7)2+(24)2 = (7i^+24j^)25V→ = 50.(7i^+24j^)25 = 2(7i^+24j^) m/s

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