A particle with charge $$-5.60$$ nC is moving in a uniform magnetic field B→$$=$$−$$1.25Tk^$$ . The magnetic force on the particle is measured to be F→$$=$$−$$(3.36$$×$$10$$−$$7N)i^+(7.42$$×$$10$$−$$7N)j^$$. Calculate one of the components of velocity of the particle from this information.

Question

A particle with charge $$-5.60$$ nC is moving in a uniform magnetic field B→$$=$$−$$1.25Tk^$$ . The magnetic force on the particle is measured to be  F→$$=$$−$$(3.36$$×$$10$$−$$7N)i^+(7.42$$×$$10$$−$$7N)j^$$. Calculate one of the components of velocity of the particle from this information.

Infinity Learn · Accepted Answer

Let velocity of the particle is  v→$$=vxi^+vyj^+vzk^Then$$  F→$$=qv$$→×B→ ⇒ −$$3.36$$×$$10$$−$$7i^+7.42$$×$$10$$−$$7j^=$$−$$5.6$$×$$10$$−$$9vxi^+vyj^+vzk^$$×$$($$−$$1.25)k^$$  ⇒ −$$3.36i^+7.42j^=7$$×$$10$$−$$2$$−$$vxj^+vyi^$$ ⇒ $$vx=$$−$$7.42$$×$$1027=$$−$$106$$ ms−$$1And$$  ⇒ $$vy=$$−$$3.36$$×$$1027=$$−$$48$$ ms−$$1$$.

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

A particle with charge -5.60 nC is moving in a uniform magnetic field B→=−1.25Tk^ . The magnetic force on the particle is measured to be F→=−(3.36×10−7N)i^+(7.42×10−7N)j^. Calculate one of the components of velocity of the particle from this information.

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material