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A particle with charge q, moving with a momentum p, enters a uniform magnetic field normally. The magnetic field has magnitude B and is confined to a region of width d, where d<  pBq. If the particle is deflected by an angle θ in crossing the field, then

a
sin θ= Bqdp
b
sin θ= pBqd
c
sin θ= Bpqd
d
sin θ= pdBq

detailed solution

Correct option is A

From figure, it is clear thatsin θ= dr,   Also  r=  pqB∴       sin θ= Bqdp

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