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A particle with restoring force proportional to displacement and resisting force proportional to velocity is subjected to a force \large F\sin \omega t. If the amplitude of a particle is maximum for frequency \large \omega \, = \,{\omega _1} while the energy is maximum for the frequency \large \omega \, = \,{\omega _2} then (where \large {\omega _o} = natural frequency of oscillation of particle)

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detailed solution

Correct option is B

In forced vibration, amplitude of oscillation is given byA=F0mω02-ωe2+ωe2bm2Amplitude when ω02-ωe2 =0     ω0=ωeHere ω0= Natural frequency of oscillationωe= Frequency of external periodic force.Again, energy of oscillation ∞A2

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In forced oscillation of a particle, the amplitude is maximum for a frequency ω1 while the energy is maximum for a frequency ω2 of the force. then

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