3 particles each of mass m are kept at vertices of an equilateral triangle of side L. The gravitational field at centre due to these particles is
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a
Zero
b
3GML2
c
9GML2
d
123 GML2
answer is A.
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Detailed Solution
Due to three particles net intensity at the centreI=I→A+I→B+I→C=0because out of these three intensities all are equal in magnitude and the angle between each other is 120°.