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Questions  

Particles of masses 2kg  and 4kg  are at  (i+j+k)  m and (i+jk) m then instantaneous position of their centre of mass is

a
16(−2i+6j−2k)
b
16(−2i−6j−2k)
c
16(2i−6j+2k)
d
16(2i+6j−3k)

detailed solution

Correct option is A

Sol:- rCM=m1r1+m2r2m1+m2                                =2(i+j+k)+4(−i+j−k)6                                =2i+2j+2k−4i+4j−4k6                              =16[−2i+6j−2k]

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