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Q.

Particles of masses 2kg  and 4kg  are at  (i+j+k)  m and (−i+j−k) m then instantaneous position of their centre of mass is

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a

16(−2i+6j−2k)

b

16(−2i−6j−2k)

c

16(2i−6j+2k)

d

16(2i+6j−3k)

answer is A.

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Detailed Solution

Sol:- rCM=m1r1+m2r2m1+m2                                =2(i+j+k)+4(−i+j−k)6                                =2i+2j+2k−4i+4j−4k6                              =16[−2i+6j−2k]
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