Particles of masses 2M, m and M are respectively at points A, B and C with AB = 1/2 (BC). m is much-much smaller than M and at time t = 0, they are all at rest as given in figure.At subsequent times before any collision takes place [NCERT Exemplar]
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a
m will remain at rest
b
m will move towards M
c
m will move towards 2M
d
m will have oscillatory motion
answer is C.
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Detailed Solution
Force on B due to A=FBA=G(2Mm)(AB)2 towards BAForce on B due to C=FBC=GMm(BC)2 towards BCAs, (BC) = 2AB⇒ FBC=GMm(2AB)2=GMm4(AB)2