Particles of masses 2M, m and M are respectively at points A, Band C with AB=12(BC) . m is much-much smaller than M and, at time t = 0, they are all at rest as given in figure. At subsequent times before any collision takes place.
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a
m will remain at rest
b
m will move towards M
c
m will move towards 2M
d
m will have oscillatory motion
answer is C.
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Detailed Solution
Force on B due to A=FBA=G(2Mm)(AB)2 towards BAForce on B due toC=FBC=GMm(BC)2 towards BCAs (BC) = 2AB⇒ FBC=GMm(2AB)2=GMm4(AB)2