Questions

Particles of masses 2M, m and M are respectively at points A, Band C with $AB = \frac{1}{2} (BC)$ . m is much-much smaller than M and, at time t = 0, they are all at rest as given in figure. At subsequent times before any collision takes place.

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m will remain at rest

m will move towards M

m will move towards 2M

m will have oscillatory motion

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detailed solution

Correct option is C

Force on B due to A=FBA=G(2Mm)(AB)2 towards BAForce on B due toC=FBC=GMm(BC)2 towards BCAs (BC) = 2AB⇒ FBC=GMm(2AB)2=GMm4(AB)2

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