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Questions  

Particles of masses m, 2m, 3m, … nm grams are placed on the same line at distance l, 2l, 3l,…. nl cm from a fixed point. The distance of centre of mass of the particles from the fixed point in centimeters is:

a
(2n+1)l3
b
ln+1
c
n(n2+1)l2
d
2ln(n2+1)

detailed solution

Correct option is A

xcm = ml+2m2l+3m3l+....nmnlm+2m+...+nm       = l[1+4+9+....+n2]1+2+....+n        = l[n(n+1)(2n+1)/6]n(n+1)2 = (2n+1)l3

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