Q.
A particular hydrogen like atom has its ground state binding energy 122.4eV. If it is in ground state. Then:
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a
its atomic number is 3
b
an electron of 90 eV can excite it.
c
an electron of kinetic energy nearly 91.8 eV can be brought to almost rest by this atom.
d
an electron of kinetic energy 2.6 eV may emerge from the atom when electron of kinetic energy 125 eV collides with this atom.
answer is A.
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Detailed Solution
122.4=13.6×Z2(1)2 ⇒Z=3ΔE1→2=13.6×(3)2112−122=13.6×9×34 =91.8eV. 125=122.4+ K.E ⋅e−⇒K⋅Ee-=2.6eV
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