Q.

A particular hydrogen like atom has its ground state binding energy 122.4eV. If it is in ground state. Then:

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a

its atomic number is 3

b

an electron of 90 eV can excite it.

c

an electron of kinetic energy nearly 91.8 eV can be brought to almost rest by this atom.

d

an electron of kinetic energy 2.6 eV may emerge from the atom when electron of kinetic energy 125 eV collides with this atom.

answer is A.

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Detailed Solution

122.4=13.6×Z2(1)2 ⇒Z=3ΔE1→2=13.6×(3)2112−122=13.6×9×34      =91.8eV. 125=122.4+ K.E ⋅e−⇒K⋅Ee-=2.6eV
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