A particular hydrogen like atom has its ground state binding energy 122.4eV. If it is in ground state. Then:

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its atomic number is 3

an electron of 90 eV can excite it.

an electron of kinetic energy nearly 91.8 eV can be brought to almost rest by this atom.

an electron of kinetic energy 2.6 eV may emerge from the atom when electron of kinetic energy 125 eV collides with this atom.

answer is A.

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Detailed Solution

122.4=13.6×Z2(1)2 ⇒Z=3ΔE1→2=13.6×(3)2112−122=13.6×9×34 =91.8eV. 125=122.4+ K.E ⋅e−⇒K⋅Ee-=2.6eV

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