Questions
A partition divides a container having insulated walls into two compartments I and II. The same gas fills the two compartments whose initial parameters are given. The partition is a conducting wall which can move freely without friction. Which of the following statements is/are correct, with reference to the final equilibrium position?
detailed solution
Correct option is A
In the equilibrium position, the net force on the partition will be zero. Hence pressure on both sides is same. Hence, (1) is correct. n1=P1V1RT1=PVRTn2=(2P)(2V)RT=4PVRT⇒n2=4n1Moles remain conserved. Finally pressure becomes equal in both the parts. Using, P1V1=n1RT1 P2V2=n2RT2P1=P2 and T1=T2V1V2=n1n2=14V2=4V1Also, V1+V2=3V ⇒ V1+4V1=3V V1=35V and V2=125VHence, options (2) and (3) are correct. In compartment I: P1′V1=n1RT1P1′3V5=PVRTR(T)P1′=5PV3V=53PHence, option (4) is also correct.Similar Questions
Two containers of equal volume contain identical gases at pressures P1 and P2 and absolute temperatures T1 and T2 respectively. The vessels are joined and the gas reaches a common pressure P and a common temperature T. Then
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