A passenger is at a distance x from a bus, when the bus begins to move with a constant acceleration a. What is the minimum velocity with which the passenger should run towards the bus so as to catch it ?
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a
(2ax)
b
2ax
c
ax
d
(ax)
answer is A.
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Detailed Solution
Let v be the velocity of the passenger and the passenger catches the bus after a time t. Then, the distance covered by both is same. Hencevt=x+12at2or at2â2vt+2x=0â´ t=+2v±4v2â8ax2a=v±v2â2axat is real, when v2 - 2 a x is positive or zero. Hence minimum speed is given byv2 -2ax=0â´v=(2ax)