The path difference between the two waves y1=a1sin⁡ωt-2πxλ and y2=a2cos⁡ωt-2πxλ+ϕ is

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λ2πϕ

λ2πϕ+π2

2πλϕ−π2

2πλ(ϕ)

answer is B.

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Detailed Solution

y1=a1sin⁡ωt−2πxλy2=a2sin⁡ωt−2πxλ+ϕ+π2Phase difference =ωt−2πxλ+ϕ+π2−ωt−2πxλ=ϕ+π2 Path difference =λ2π× Phase difference =λ2πϕ+π2

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