First slide

Concept of potential energy

Question

The P.E of a conservative system is given by $V (x) = (x^{2} - 3 x) J$ , where x is measured in metre. Then its equilibrium position is at

Moderate

A

1.5 m
B

2 m
C

3 m
D

1 m

Solution

$g i v e n P E i s V (x) = x^{2} - 3 x A t e q u i l i b r i u m, t h e P . E o f a s y s t e m i s m i n i m u m, t o f i n d m a x i m u m o r m i n i m u m v a l u e o f P E, d i f f e r e n t i a t e P E a n d e q u a t e t o z e r o ∴ \frac{d v}{d x} = 0 \Rightarrow \frac{d}{d x} (x^{2} - 3 x) = 0 \Rightarrow 2 x - 3 = 0 \Rightarrow x = \frac{3}{2} \Rightarrow x = 1.5 m$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App