Q.
The P.E of a conservative system is given by V(x) = (x2−3x) J, where x is measured in metre. Then its equilibrium position is at
see full answer
Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!
Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya
a
1.5 m
b
2 m
c
3 m
d
1 m
answer is A.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
given PE is V(x)=x2−3x At equilibrium , the P.E of a system is minimum, to find maximum or minimum value of PE , differentiate PE and equate to zero ∴ dvdx = 0 ⇒ ddx (x2−3x) = 0 ⇒ 2x − 3 = 0 ⇒ x = 32 ⇒x = 1.5 m
Watch 3-min video & get full concept clarity