The P.E of a conservative system is given by V(x) $$=$$ (x2$$−$$3x) J, where x is measured in metre. Then its equilibrium position is at

Question

The P.E of a conservative system is given by  V​(x)  $$=$$   (x2$$−$$3x) J, where x is measured in metre.  Then its equilibrium position is at

Infinity Learn · Accepted Answer

given $$PE$$ is $$V(x)=x2$$−$$3x$$ At equilibrium , the P.E of a system is minimum, to find maximum or minimum value of $$PE$$ , differentiate $$PE$$ and equate to zero ∴      dvdx   $$=$$    $$0$$     ⇒    ddx   (x2$$−$$3x)   $$=$$    $$0$$ ⇒  $$2x$$  − $$3$$  $$=$$   $$0$$ ⇒   x  $$=$$    $$32$$   ⇒x    $$=$$   $$1.5$$ m

The P.E of a conservative system is given by $V (x) = (x^{2} - 3 x) J$ , where x is measured in metre. Then its equilibrium position is at

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The P.E of a conservative system is given by V​(x) = (x2−3x) J, where x is measured in metre. Then its equilibrium position is at

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The P.E of a conservative system is given by $V (x) = (x^{2} - 3 x) J$ , where x is measured in metre. Then its equilibrium position is at