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Q.

The P.E of a conservative system is given by  V​(x)  =   (x2−3x) J, where x is measured in metre.  Then its equilibrium position is at

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a

1.5 m

b

2 m

c

3 m

d

1 m

answer is A.

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Detailed Solution

given PE is V(x)=x2−3x At equilibrium , the P.E of a system is minimum, to find maximum or minimum value of PE , differentiate PE and equate to zero ∴      dvdx   =    0     ⇒    ddx   (x2−3x)   =    0 ⇒  2x  − 3  =   0 ⇒   x  =    32   ⇒x    =   1.5 m
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