The P.E of a conservative system is given by V(x) = (x2−3x) J, where x is measured in metre. Then its equilibrium position is at
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a
1.5 m
b
2 m
c
3 m
d
1 m
answer is A.
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Detailed Solution
given PE is V(x)=x2−3x At equilibrium , the P.E of a system is minimum, to find maximum or minimum value of PE , differentiate PE and equate to zero ∴ dvdx = 0 ⇒ ddx (x2−3x) = 0 ⇒ 2x − 3 = 0 ⇒ x = 32 ⇒x = 1.5 m