First slide

Work done by Diff type of forces

Question

The PE stored in a long spring stretched by 1 cm is U. If the spring is stretched by 3 cm instead, its PE will be :

Easy

A

9U
B

3U
C

U/3
D

U/9

Solution

$U = \frac{1}{2} k (1)^{2} \Rightarrow U^{'} = \frac{1}{2} k (3)^{2} = \frac{9}{2} k = 9 U$

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