First slide

Alternating Current and voltage

Question

The peak value of an alternating e.m.f. E is given by $E = E_{0} cosω t$ is 10 volts and its frequency is 50 Hz. At time $t = \frac{1}{600} \sec$ , the instantaneous e.m.f. is

Moderate

A

10 V
B

$5 \sqrt{3} V$
C

5 V
D

1 V

Solution

$E = E_{0} cosωt = E_{0} \cos \frac{2 πt}{T}$
$= 10 \cos \frac{2 π \times 50 \times 1}{600} = 10 \cos \frac{π}{6} = 5 \sqrt{3} volt .$

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