A pebble is thrown vertically upwards from a bridge with an initial velocity of 4.9 m/s. It strikes the water after 2 s. The height of the bridge is:
19.6 m
14.7 m
9.8 m
4.9 m
By using s=ut+12at2 and taking upward as positive directionWe have -h=4.9 (2)+12-9.822⇒h=9.8m