First slide

Potential energy

Question

A pendulum bob of mass 500 gm is suspended by a string of length 2 m. A horizontal force slowly displaces the bob from position A to position B as shown in the figure. Then work done by the applied force is …….if g=10 m $s^{- 2}$

Moderate

A

7.5 J
B

10 J
C

5 J
D

2.5 J

Solution

Work done by the applied force
= change in potential energy
$= mgh = mgl (1 - \cos 60^{o}) = 0 .5 \times 10 \times 2 \times (1 - \frac{1}{2}) J = 5 J$

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