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Q.

A pendulum bob of mass 30.7×10−6 kg and carrying a charge 2×10−8 C is at rest in a horizontal uniform electric field of 20000 V/m. The tension in the thread of the pendulum is (g=9.8 m/s2)

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a

3×10−4 N

b

4×10−4 N

c

5×10−4 N

d

6×10−4 N

answer is C.

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Detailed Solution

T=(mg)2+(QE)2=30.7×10−6×9.82+2×10−8×200002=5×10−4N
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