A pendulum of bob of Mass 80mg and carrying a charge of 2×10−8C is at rest in a uniform horizontal electric field of 20kVm−1 . Find the tension in the string

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Detailed Solution

At equilibrium Tcosθ=mg and Tsinθ=Eq ∴T2=mg2+Eq2 T=80×10−6×102+20×103×2×10−82 =80×10−8 =8.8×10−4N

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