A pendulum of bob of Mass 80mg and carrying a charge of 2×10−8C is at rest in a uniform horizontal electric field of 20kVm−1 . Find the tension in the string

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 1.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

At equilibrium Tcosθ=mg and Tsinθ=Eq ∴T2=mg2+Eq2 T=80×10−6×102+20×103×2×10−82 =80×10−8 =8.8×10−4N

Watch 3-min video & get full concept clarity