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A pendulum clock (fitted with a small heavy bob that is connected with a metal rod) is 5 seconds fast each day at a temperature of 15oC  and 10 seconds slow at a temperature of 30oC . The temperature at which it is designed to give correct time, is

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a
18oC
b
20oC
c
24oC
d
25oC

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detailed solution

Correct option is B

12α(T0−15)×24hr=5...........(i)12α(30−T0)×24hr=10..........(ii)Solving equations (i) and (ii), we get  T0=200C


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