A pendulum clock runs fast by 5 seconds per day at 200c and goes slow by 10 seconds per day at 35°C. It shows correct time at a temperature of

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27.5°C

25.°C

30.°C

33.°C

answer is B.

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Detailed Solution

12a(35−t)×86400=10 ...(1)12a(t−20)×86400=5 ...(2)Solving 1 and 2

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