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Questions  

A pendulum clock runs fast by 5 seconds per day at 200c and goes slow by 10 seconds per day at 35°C. It shows correct time at a temperature of

a
27.5°C
b
25.°C
c
30.°C
d
33.°C

detailed solution

Correct option is B

12a(35−t)×86400=10   ...(1)12a(t−20)×86400=5   ...(2)Solving 1 and 2

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