A pendulum clock is 5 second fast at temperature of 15oC and 10 second slow at a temperature of 300oC At what temperature does it give the correct time ?
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a
18°C
b
20°C
c
22°C
d
25°C
answer is B.
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Detailed Solution
Δt=12αΔT ∴5=12α(T−15)×86400 and 10=12α(T−30)×86400 Solving, we get T=20oC