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Q.

A pendulum clock is 5 second fast at temperature of 15oC and 10 second slow at a temperature of 300oC At what temperature does it give the correct time ?

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a

18°C

b

20°C

c

22°C

d

25°C

answer is B.

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Detailed Solution

Δt=12αΔT ∴5=12α(T−15)×86400 and    10=12α(T−30)×86400 Solving, we get T=20oC
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