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Questions  

A pendulum clock is 5 second fast at temperature of 15oC and 10 second slow at a temperature of 300oC At what temperature does it give the correct time ? 

a
18°C
b
20°C
c
22°C
d
25°C

detailed solution

Correct option is B

Δt=12αΔT ∴5=12α(T−15)×86400 and    10=12α(T−30)×86400 Solving, we get T=20oC

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