First slide

Thermal expansion

Question

A pendulum clock is 5 second fast at temperature of 15^oC and 10 second slow at a temperature of 300^oC At what temperature does it give the correct time ?

Easy

A

18°C
B

20°C
C

22°C
D

25°C

Solution

$Δt = \frac{1}{2} αΔT ∴ 5 = \frac{1}{2} α (T - 15) \times 86400 and 10 = \frac{1}{2} α (T - 30) \times 86400 Solving, we get T = 20^{o} C$

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