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A pendulum consists of a wooden bob of mass m and length $' ℓ'$ . A bullet of mass $m_{1}$ is fired towards the pendulum with a speed $v_{1}$ . The bullet emerges out of the bob with a speed $v_{1}$ / 3 , and the bob just completes motion along a vertical circle. Then $v_{1}$ is

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mm15gℓ

32mm15gℓ

23m1m5gℓ

m1mgℓ

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detailed solution

Correct option is B

Using conservation of momentum,m1v1+0=m1v13+mv⇒m1v1−m1v13=mv(v=5gl to complete motion along vertical circle) ⇒2 m1v13=mv⇒v=23m1v1 m or v1=32mm15gl

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A pendulum consists of a wooden bob of mass m and length 'ℓ '. A bullet of mass m1 is fired towards the pendulum with a speed v1. The bullet emerges out of the bob with a speed v1/ 3 , and the bob just completes motion along a vertical circle. Then v1is

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Ready to Test Your Skills?

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A pendulum consists of a wooden bob of mass m and length $' ℓ'$ . A bullet of mass $m_{1}$ is fired towards the pendulum with a speed $v_{1}$ . The bullet emerges out of the bob with a speed $v_{1}$ / 3 , and the bob just completes motion along a vertical circle. Then $v_{1}$ is