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A pendulum consists of a wooden bob of mass m and length I . A bullet of mass m is fired towards the pendulum with a speed v1 .The bullet emerges out of the bob with a speed v13, and the bob completes a motion along a vertical circle. then v1 is 

a
mm1(5gl)
b
32mm1 (5gl)
c
23m1m(5gl)
d
m1m(gl)

detailed solution

Correct option is B

Applying the law of conservation of momentummv=m1⋅v1−v13 ∴ v=m1m2v13  To describe a vertical circle, v should be (5gl). Hence  (5gl)=m1m23v1 v1=mm132(5gl)

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A pendulum of length / = l m is released from θ0 = 600. The rate of change of speed of the bob at θ = 300 is (g = 10 m/s2)


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