First slide

Periodic Motion

Question

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s² at a distance of 5 m from the mean position. The time period of oscillation is

Easy

A

$2 πs$
B

$π s$
C

$2 s$
D

$1 s$

Solution

$|a| = ω^{2} x \Rightarrow 20 = ω^{2} 5 \Rightarrow ω^{2} = 4 \Rightarrow ω = 2 \Rightarrow \frac{2 π}{T} = 2 \Rightarrow T = πs$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App