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A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m s-2 at a distance of 5 m from the mean position. The time period of oscillation is

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By Expert Faculty of Sri Chaitanya
a
2πs
b
πs
c
2 s
d
1 s

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detailed solution

Correct option is B

Magnitude of acceleration of a particle moving in a SHM is|a|=ω2y; where y is amplitude. ⇒20=ω2(5)⇒ω=2rads-1∴Time period of oscillationT=2πω=2π2=π sec
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