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Q.

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m s-2 at a distance of 5 m from the mean position. The time period of oscillation is

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a

2πs

b

πs

c

2 s

d

1 s

answer is B.

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Detailed Solution

Magnitude of acceleration of a particle moving in a SHM is|a|=ω2y; where y is amplitude. ⇒20=ω2(5)⇒ω=2rads-1∴Time period of oscillationT=2πω=2π2=π sec
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