A pendulum of length / = l m is released from θ0 = 600. The rate of change of speed of the bob at θ = 300 is (g = 10 m/s2)

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53 m/s2

5 m/s2

10 m/s2

2.5 m/s2

answer is B.

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Detailed Solution

Rate of change of speeddvdt = tangential acceleration = tangential forcemass = mg sin 300m = g sin 300 = 10(12)m/s2 = 5 m/s2

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