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A pendulum of length l = 1 m is released from $θ_{0} = 60^{0}$ . The rate of change of speed of the bob at $θ = 30^{0}$ is (g = $10 m / s^{2}$ )

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53 m/s2

5 m/s2

10 m/s2

2.5 m/s2

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detailed solution

Correct option is B

at any position in a vertical circular motion speed changes due to tangential acceleration which is g sinθ10 sin300 = 5

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A pendulum of length l = 1 m is released from θ0=600. The rate of change of speed of the bob at θ =300is (g =10 m/s2)

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A pendulum of length l = 1 m is released from $θ_{0} = 60^{0}$ . The rate of change of speed of the bob at $θ = 30^{0}$ is (g = $10 m / s^{2}$ )