Questions
A pendulum of length 2m released at P. When it reaches Q, it losses 10% of its total energy due to air resistance. The velocity at Q is
detailed solution
Correct option is A
If v is velocity of pendulum at Q and 10% energy is lost while moving from P to Q Hence, by applying conservation of between P and Q12mv2=0.9 (mgh)⇒v2=2×0.9×10×2⇒v=6 m/secTalk to our academic expert!
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A simple pendulum has time period T1. The point of suspension is now moved upward according to equation where . If new time period is T2 then ratio will be
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