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Q.

A pendulum of mass m hangs from a support fixed to a trolley. The direction of the string (i.e. angle θ) when the trolley rolls up a plane of inclination α with acceleration a is

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a

0

b

tan-1 α

c

tan-1 a + g sin αg cos α

d

tan-1 ag

answer is C.

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Detailed Solution

Tsinθ-mgsinα=maand Tcosθ=mgcosαFrom these two equations, we gettanθ=a+gsinαgcosα⇒θ=tan-1a+gsinαgcosα
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