Questions
A pendulum is oscillating in a vertical plane. The acceleration at the extreme position and lowest position are equal. Then the angular amplitude of the pendulum is
a
tan−12
b
tan−12
c
tan−11/2
d
2tan−112
detailed solution
Correct option is D
acceleration at the extreme position gsinθ and lowest position v2l . gsinθ=v2l From conservation of energy 12mv2=mgl1−cosθmv2l=2mg1−cosθgsinθ=2g1−cosθsinθ=4sin2θ22sinθ2cosθ2=4sin2θ2tanθ2=12θ2=tan−112θ=2tan−112Talk to our academic expert!
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