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A pendulum is oscillating in a vertical plane. The acceleration at the extreme position and lowest position are equal. Then the angular amplitude of the pendulum is
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Correct option is D
acceleration at the extreme position gsinθ and lowest position v2l . gsinθ=v2l From conservation of energy 12mv2=mgl1−cosθmv2l=2mg1−cosθgsinθ=2g1−cosθsinθ=4sin2θ22sinθ2cosθ2=4sin2θ2tanθ2=12θ2=tan−112θ=2tan−112Similar Questions
A pendulum of length / = l m is released from . The rate of change of speed of the bob at is (g = 10 )
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