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A pendulum is undergoing SHM. The velocity of the bob in the mean position is V0. If now its amplitude is doubled, keeping the length same, its velocity in the mean position will be:

a
V0/2
b
2V0
c
V0
d
4/V0

detailed solution

Correct option is B

At mean position V=aωWhen A'=2A,V'=2V0

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