First slide

Internal energy

Question

As per law of equipartition of energy, energy associated with each molecule having f degrees of freedom is

Easy

A

$\frac{f}{4} R T$
B

$\frac{f}{2} R T$
C

$\frac{f}{2} k T$
D

$\frac{3}{2} k T$

Solution

Energy per molecule per degree of freedom = $\frac{1}{2} k T$ .
Hence, energy per molecule per degree of freedom = $\frac{f}{2} k T$ .

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